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Question

The escape velocity for a body projected vertically upwards from the surface of earth is 11 km/s. If the body is projected at an angle of 450 with the vertical, the escape velocity will be

A
112km/s
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B
22 km/s
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C
11 km/s
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D
11/2 km/s
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Solution

The correct option is B 11 km/s
Escape speed of a body from Earth's surface is given by: vmin=2gR
This expression is obtained by conservation of energy and doesn't involve in which direction the body is thrown/projected.
So, irrespective of the angle of projection, escape speed of the body from Earth's surface remains constant i.e. 11 km/s

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