The escape velocity of a projectile from the earth is approximately

7

k m / s e c

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112

k m / s e c

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11.2

k m / s e c

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1.1

k m / s e c

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Solution

The correct option is B $11.2$ $k m / s e c$
The escape velocity of projectile from earth is
$v_{e} = \sqrt{2 g R_{e}}$ , where $R_{e}$ is radius of earth
since $g = 9.8 m / s e c^{2}, R_{e} = 6.4 \times 10^{6}$ metre
$\Rightarrow v_{e} = 11.2 k m / s e c$

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The escape velocity of a projectile from the earth is approximately

The correct option is B 11.2 km/secThe escape velocity of projectile from earth isve=√2gRe, where Re is radius of earthsince g=9.8m/sec2,Re=6.4×106 metre⇒ve=11.2km/sec

The correct option is B $11.2$ $k m / s e c$
The escape velocity of projectile from earth is
$v_{e} = \sqrt{2 g R_{e}}$ , where $R_{e}$ is radius of earth
since $g = 9.8 m / s e c^{2}, R_{e} = 6.4 \times 10^{6}$ metre
$\Rightarrow v_{e} = 11.2 k m / s e c$