You visited us 1 times! Enjoying our articles? Unlock Full Access!

nCr Definitions and Properties

The expansion...

Question

The expansion of $(4 p + 5 q)^{8}$ by using binomial theorem

\sum_{r = 0}^{9}^{8} C_{r} (4 p)^{r} (5 q)^{8 - r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sum_{r = 0}^{8}^{8} C_{r} (5 q)^{r} (4 p)^{8 - r}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sum_{r = 0}^{6} (- 1)^{r}^{8} C_{r} (4 p)^{r} (5 q)^{8 - r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sum_{r = 0}^{7} (- 1)^{r}^{8} C_{r} (5 q)^{r} (4 p)^{8 - r}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $\sum_{r = 0}^{8}^{8} C_{r} (5 q)^{r} (4 p)^{8 - r}$
The expansion of $(4 p + 5 q)^{8}$ by using binomial theorem is
$\sum_{r = 0}^{8}^{8} C_{r} {(5 q)}^{r} {(4 p)}^{8 - r}$

Suggest Corrections

Similar questions

Q. The ratio of the coefficient of terms

x^{n - r} a^{r}

and

x^{r} a^{n - r}

in the binomial expansion of

(x + a)^{n}

will be

If the coefficients of $x^{r - 1}, x^{r}$ and $x^{r + 1}$ in the binomial expansion of $(1 + x)^{n}$ are in AP, prove that
$n^{2} - n (4 r + 1) + 4 r^{2} - 2 = 0$

What is the general term in the binomial expansion of (1+2x)ⁿ

Q. If the coefficients of

r^{t h}, (r + 1)^{t h} a n d (r + 2)^{t h}

terms in the binomial expansion of

(1 + y)^{m}

are in A.P., then

m

and

r

satisfy the equation

Q. If the coefficients of

r^{t h}

(r + 1)^{t h}

and

(r + 2)^{t h}

terms in the binomial expansion of

(1 + y)^{m}

are in

A . P .

, then

m

and

r

will satisfy the equation

Join BYJU'S Learning Program

The expansion of (4p+5q)8 by using binomial theorem

The correct option is D ∑8r=08Cr(5q)r(4p)8−rThe expansion of (4p+5q)8 by using binomial theorem is∑8r=08Cr(5q)r(4p)8−r

The expansion of $(4 p + 5 q)^{8}$ by using binomial theorem

The correct option is D $\sum_{r = 0}^{8}^{8} C_{r} (5 q)^{r} (4 p)^{8 - r}$
The expansion of $(4 p + 5 q)^{8}$ by using binomial theorem is
$\sum_{r = 0}^{8}^{8} C_{r} {(5 q)}^{r} {(4 p)}^{8 - r}$