Question

The experimental molecular weight of an electrolyte will always be less than its calculated value because the value of Van't Hoff factor "i” is

• A. Less than 1
• B. Greater than 1
• C. Equivalent to one
• D. Zero

Answer 1

Correct option: (B)

• Van't Hoff factor is used for determining the extent up to which a molecule undergoes association or dissociation.
• It is represented by ${}^{\prime }{i}^{\prime }$.
• $i=\frac{\text{Calculated molecular weight}}{\text{Experimental molecular weight}}$
• Given: $\text{Experimental moleculer weight}<\text{Calculated molecular weight}$
• Hence, van't hoff factor is greater than 1.

Hence, the correct option is (B).