Question

The experimental value of the dipole moment of $HCl$ is 1.03 D. the length of the $H-Cl$ bond is 1.275A. the percentage of ionic character in $HCl$ is:

• A. 43
• B. 21
• C. 17
• D. 7

Answer 1

The correct option is C 17

$\mu =e\times d$

For Complete seperation of unit charge , the dipole moment is calculated as

$\mu =1.6\times {10}^{-19}\times 1.275\times {10}^{-10}$

$\mu =2.04Cm$

Actual Dipole moment = 1.03 D = $0.34\times {10}^{-29}Cm$

% Ionic character = $\frac{0.34\times {10}^{-29}}{2.04\times {10}^{-29}}\times 100$ = 17%