The expression a x2-b x-ca- b and c are real has the same sign as that of a for all x is A- b 2-4 ac -0B- b 2-4 a -0C- b 2-4 ac - 0D- b and c have the same sign as that of a

The correct option is C b^2 4ac ≤ 0 ...

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Binomial Theorem

The expressio...

Question

The expression $a x^{2} + b x + c$ ( $a, b$ and $c$ are real) has the same sign as that of a for all $x$ is

b^{2} - 4 a c > 0

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b^{2} - 4 a c \neq 0

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b^{2} - 4 a c \leq 0

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b

and

c

have the same sign as that of

a

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Solution

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Similar questions

y = a x^{2} + b x + c

y =

A x^{2} + B x + C

a

A

b^{2} - 4 a c

B^{2} - 4 A C

y = a x^{2} + b x + c

What is the condition for the equation $x^{2} + b x - c = 0$ to have real roots?

a x^{2} + b x + c = 0; a, b, c \in R,

Δ = b^{2} - 4 a c

a x^{2} + b x + c = 0 ?

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