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Question

The factorisation of 2y3+10y2−48y is ____.

A
2y(y3)(y+8)
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B
2y(y+3)(y+8)
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C
2y(y3)(y8)
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D
2y(y+3)(y8)
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Solution

The correct option is A 2y(y3)(y+8)
2y3+10y248y
on taking 2ycommon from all the terms;
=2y(y2+5y24)
Now, using the method of middle term splitting;
=2y(y2+8y3y24)
=2y[y(y+8)3(y+8)]
=2y(y3)(y+8)

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