The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is
(a) 72 cm2 (b) 36 cm2 (c) 24 cm2 (d) 18 cm2
It is clear from the figure that quadrilateral ABCD is a parallelogram. The diagonal AC of the given parallelogram ABCD divides it into two triangles of equal areas.
Area of the ΔABC=12×Base×Height
∴ Area of the parallelogram ABCD=2×Area of ΔABC