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Question 16

The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is 

(a) 72 cm2               (b) 36 cm2              (c) 24 cm2            (d) 18 cm2


Solution

It is clear from the figure that quadrilateral ABCD is a parallelogram. The diagonal AC of the given parallelogram ABCD divides it into two triangles of equal areas.
Area of the ΔABC=12×Base×Height
=12×12×3=18cm2
Area of the parallelogram ABCD=2×Area of ΔABC
                                                               =2×18
                                                                =36 cm2


Mathematics
NCERT Exemplar
Standard VIII

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