The figure shows a part of a complete circuit. The potential difference VB–VA when the current I is 5A and is decreasing at a rate of 103As–1 is given by
A
15V
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B
10V
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C
−15V
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D
20V
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Solution
The correct option is C−15V The circuit can be redrawn as shown.
From Kirchhoffs voltage law VA−1×5−15+5=VB VB−VA=−15V