The first term and last term number is $12$ and $30$ . The total number of term is $50$ . Find its sum.

1, 100

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1, 250

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1, 150

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1, 050

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Solution

The correct option is B $1, 050$
Given, $n = 50$ , first term $= 12$ and last term $= 30$
Sum of first $n$ numbers of an A.P. is
$S_{n} = \frac{n}{2} [2 a + (n - 1) d]$ or $\frac{n}{2}$ [First term $+$ Last term]
$= \frac{50}{2} [12 + 30]$
$= 25 [42]$
$S_{50} = 1, 050$

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