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Question

The first term of an A.P. is 5, the common difference is 3 and the last term is 80; find the number of terms ?


Solution

Given : a = 5

d = 3

an= last term  = 80

(i) Let there be n terms

an=80=a+(n1)d

=80=5+(n1)3

75=(n1)3

25=(n1)

n=26

Thus, there are 26 terms in the given sequence.

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