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Question

The first three terms of an AP respectively are 3y1,3y+5 and 5y+1. Then y equals :

A
3
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B
4
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C
5
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D
2
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Solution

The correct option is C 5
Given 3y1,3y+5 & 5y+1 are in A.P
So :- difference between then
3y+5(3y1)=5y+1(3y+5)
3y+53y+1=5y+13y5
6=2y4
2y=10
y=5

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