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Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor if the cost per m2 is Rs.4.

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Solution

Given diagonals of rhombus are
d1=45cm
d2=30cm
Number of tiles = 3000
Rate per m2=4

Area of rhombus =12×d1×d2
=12×45×30
=675cm2

Area of 1 tile =675cm2=67510000m2.......[1cm2.11000m2]

Area of 3000 tiles =[3000×67510000]

Cost of polishing the floor =Total Area×Rate

=3000×675×410000

=3×675×410

=12×67.5

=Rs.810

Hence the total cost of polishing the floor = Rs.810

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