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Question

The floor of a building consists of around 3000 tiles which are rhombus shaped and each of its diagonals are 45cm and 30cm in length. Find the total cost of flooring if each tile costs rupees 20 per m2

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Solution


Let d1=45cm and d2=30cm be the two diagonals of the rhombus respectively.

Area of each tile = d1×d22=45×302=675cm2

Area of 3000 tiles = 300×675=2025000cm2=202.5m2

Cost of flooring = Rs.(202.5×20)=Rs.4050




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