The following are the heights in centimetres of the students in class X.
162, 155, 166, 173, 170, 161, 166, 151, 167, 176, 178, 175, 163, 165, 170, 152, 172, 166, 176, 159, 157, 158, 148, 174, 152, 162, 171, 178, 157, 145, 148.
The given data has been grouped into class intervals in the given frequency distribution table.
Fill in the table with the missing frequencies.
Class intervalFrequency(fi)145−1503150−1553155−160p=−−−−160−165q=−−−−165−170r=−−−−170−175s=−−−−175−1805
p = 5, q = 4, r = 5, s = 6
The data provided is:
162, 155, 166, 173, 170, 161, 166, 151, 167, 176, 178, 175, 163, 165, 170, 152, 172, 166, 176, 159, 157, 158, 148, 174, 152, 162, 171, 178, 157, 145, 148.
Counting the number of values present in the range of 155 -160 in the given data, we obtain p = 5.
Similarily, q=4
r=5 s=6