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Question

The following diagram shows an incident ray AO and the normal ON on a plane mirror. Find the angle of incidence and angle of reflection. 
1800056_8c980f1a7cf74d8ba8d50113bae50f37.png


Solution

ON is perpendicular on a plane mirror 
Angle of Incidence $$\angle i (\angle AON)$$i.e.
Angle between incident ray and normal ray = $$90^0 - 30^0 = 60^0$$ 
Angle of Reflection = $$60^0$$ 
$$\therefore \ \ \angle i = \angle r$$ 
$$\therefore$$ Angle between Incident and reflected ray I.e. $$\angle AOB$$
= $$60 + 60 = 120^0$$ 
1680970_1800056_ans_c5b77dac460442558ce0c3b1800d2a85.png

Physics
NCERT
Standard XII

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