Question

# The following figure represents a solid consisting of a right circular cylinder with a hemisphere at one end and a cone at the other. Their common radius is $$7$$cm. The height of the cylinder and cone are each of $$4$$cm. Find the volume of the solid.

Solution

## The solid can be divided into $$3$$ parts.The first part is the cone with height $$4\;cm$$ and radius $$7\;cm$$.Volume of cone  $$\displaystyle V_1=\dfrac{1}{3}\pi r^2 h\\ = \dfrac{1}{3}\cdot \dfrac{22}{7}\cdot 7^2 \cdot 4\\= 205.34\; cm^3$$The second part is the cylinder with height $$4\;cm$$ and radius $$7\;cm$$.Volume of cylinder $$\displaystyle V_2=\pi r^2 h\\=\dfrac{22}{7} \cdot 7^2 \cdot 4 \\= 616\; cm^3$$The third part is the hemisphere with radius $$7\;cm$$.Volume of hemisphere  $$\displaystyle V_3=\dfrac{2}{3}\pi r^3\\ = \dfrac{2}{3}\cdot \dfrac{22}{7}\cdot 7^3\\= 718.67\;cm^3$$Volume of total solid $$V_1+V_2+V_3=1540\; cm^3$$Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More