    Question

# The following table gives the marks obtained by 300 students of a management course. Find the median of the distribution.Marks obtainedNo. of students0−152615−303430−456445−607660−756075−906090−10010

A
62.96 marks
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B
62.13 marks
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C
50.13 marks
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D
50.96 marks
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Solution

## The correct option is C 50.13 marksMedian is the middle most value of a given series that represents the whole class of the series. For a group data, Median = L + [{(n/2) – B}/G] × w where Lis the lower class boundary of the group containing the mediannis the total number of valuesBis the cumulative frequency of the groups before the median groupGis the frequency of the median groupwis the group widthSince the median is the middle value, which in this case is 165th one , which is in the 45-60 group. Therefore , 45-60 is the median group so L= 45n= 330B= 26 + 34 + 64 = 124 G= 76 w= 15 Median= 45 + [{(330/2) – 124}/76] × 15 = 45 + 8.09 = 53.09  Suggest Corrections  0      Similar questions
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