Question

# The following table shows the frequency distribution of the diameters of 40 bottles. Find the mean of the data. Diameter (mm)35−3940−4445−4950−5455−60Frequency61215107

A
45
B
37
C
47
D
55

Solution

## The correct option is D 47Diameter(mm)35−3940−4445−4950−5455−60Frequency(f)61215107Mid-Point(x)3742475257fx222504705520399 Here, the mid-point of each interval =Lower class limit + Upper class limit2 =35+392=37 Similarly, we can find mid-points of all the class interval. Now Mean=∑fixi∑fi Mean=222+504+705+520+39950=235050 ∴Mean=47

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