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Question

The force required to just move a body up the inclined plane is double the force required to just prevent the body from sliding down the plane. If the coefficient of friction is μ, then inclination θ of the plane is


A
tan1μ
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B
tan1(μ2)
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C
tan12μ
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D
tan13μ
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Solution

The correct option is C tan13μ
For both the cases, friction force, f=μN=μmgcosθ


Force required to pull upwards,
F1=(mgsinθ+μmgcosθ)


Force required to stop sliding,
F2=(mgsinθμmgcosθ)

Since F1=2F2
(mgsinθ+μmgcosθ)=2(mgsinθμmgcosθ)
tanθ=3μ
θ=tan1(3μ)

Physics

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