The formula for the members of homologous series beginning with acetone $(C H_{3} C O C H_{3})$ is:

C H_{3} - C O - C H_{2} - C H_{3}

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C H_{3} - C H (O H) - C H_{3}

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C H_{3} - O - C H_{3}

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C H_{3} - C H_{2} - O - C H_{3}

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Solution

The correct option is A $C H_{3} - C O - C H_{2} - C H_{3}$
The given compound is a starting member of the ketone family.

$C H_{3} C O C H_{3}$

The homologous series of the given compound is following:

i. $C H_{3} - C O - C H_{2} C H_{3}$ (Butan-2-one)

ii. $C H_{3} - C O - C H_{2} C H_{2} C H_{3}$ (Pentan-2-one)

iii. $C H_{3} C O C_{4} H_{9}$ (Hexan-2-one)

iv. $C H_{3} C O C_{5} H_{11}$ (Heptan-2-one)

Hence, the correct option is A.

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