Question

# The formula for the members of homologous series beginning with acetone $$(CH_3COCH_3)$$ is:

A
CH3COCH2CH3
B
CH3CH(OH)CH3
C
CH3OCH3
D
CH3CH2OCH3

Solution

## The correct option is A $$CH_3-CO-CH_2-CH_3$$The given compound is a starting member of the ketone family.$$CH_3COCH_3$$The homologous series of the given compound is following: i.$$CH_3−CO−CH_2CH_3$$ (Butan-2-one)ii. $$CH_3−CO−CH_2CH_2CH_3$$ (Pentan-2-one)iii. $$CH_3COC_4H_9$$ (Hexan-2-one)iv. $$CH_3COC_5H_{11}$$ (Heptan-2-one)Hence, the correct option is A.Chemistry

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