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Question

The frequencies of three tuning forks A, B and C have a relation $$n_{A}>n_{B}>n_{c}$$. When the forks A and B are sounded together the number of beats produced is n$$_{1}$$. When A and C are sounded together the number of beats produced is n$$_{2}$$, then the number of beats produced when B and C are sounded together is


A
nJ+n2
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B
n1+n22
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C
n2n1
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D
n1n2
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Solution

The correct option is B $$n_{2}-n_{1}$$
No. of beats produced, $$n=n_{1}- n_{2}$$
When A and B are sounded, $$n_{1}=n_{A}- n_{B}$$
When A and C are sounded, $$n_{2}=n_{A}- n_{C}$$
When B and C are sounded: 
$$n=n_{B}- n_{C}$$
    $$=(n_{A}- n_{C})-(n_{A}- n_{B})$$
    $$=n_{2}-n_{1}$$

Physics

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