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Question

The frequencies of two sound sources are 256 Hz and 260Hz . At t=0, the intensity of sound is maximum. Then the phase difference at the time t=1/16 sec will be

A
Zero
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B
π
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C
π/2
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D
π/4
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Solution

The correct option is D π/2
Time interval between two consecutive beats
T=1n1n2=1260256=14sec

so, t=116=T4 sec

By using time difference =T2π× Phase difference

T4=T2π×ϕ

ϕ=π2

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