CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The frequency of radiation emitted when the electron falls from $$n=4$$ to $$n=1$$ in a hydrogen atom will be (given ionization energy of $$H=2.18\times 10^{-18} J\ atom^{1}$$ and $$h=6.625\times 10^{-34}\ J\ s$$


A
1.54×1015s1
loader
B
1.03×1015s1
loader
C
3.08×1015s1
loader
D
2.00×1015s1
loader

Solution

The correct option is C $$3.08\times 10^{15}s^{-1}$$
Hence, Option "C" is the correct answer.
1701700_1740967_ans_5fa4656909f94e3da1b277db3b10dace.jfif

Chemistry
NCERT
Standard XII

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image