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Question

The frequency of revolution of electron in nth Bohr orbit is Vn. The graph between log n and log(VnV1) may be


Solution

The correct option is C
We know that 
vZn
and rn2Z
Hence v and r can be written as 
v=c1Zn and r=c2n2Z, where both c1 and c2 are constants. 

We know that Frequency Vn=1T=v2πr
Hence V can be written as Vn=cn3

Now, VnV1=n3
logVnV1=3 log n

Hence graph between log n and log(VnV1) will be a linear graph with negative slope passing through origin.

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