Question

# The frequency of revolution of electron in nth Bohr orbit is Vn. The graph between log n and log(VnV1) may be

Solution

## The correct option is C We know that  v∝Zn and r∝n2Z Hence v and r can be written as  v=c1Zn and r=c2n2Z, where both c1 and c2 are constants.  We know that Frequency Vn=1T=v2πr Hence V can be written as Vn=cn−3 Now, VnV1=n−3 ∴logVnV1=−3 log n Hence graph between log n and log(VnV1) will be a linear graph with negative slope passing through origin.

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