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Question

The frequency of the spectral line obtained when the electron in n=3 of Hydrogen atom drops to the fround state is:

A
2.925×1015Hertz
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B
2.925×1013Hertz
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C
2.925×1014Hertz
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D
36559×1010Hertz
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Solution

The correct option is A 2.925×1015Hertz
Energy difference= 13.6[1(1)21(3)2]eV
=12.08eV
=12.08×1.6×1019J
=1.93×1018J
hv=1.93×1018J
v=1.93×10186.63×1034=2.925×1015 Hertz

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