The function given by f(x)=3x+7x2−5x+6 is continuous in
A
(2,3]
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B
R−[2,3]
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C
R−{2,3}
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D
None of the above
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Solution
The correct option is CR−{2,3} f(x) is not defined when denominator equals 0
So, for f(x) to be continuous, x2−5x+6≠0, ⇒x≠2,3
So, f(x) is continuous for all x∈R−{2,3}