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Question

The fundamental period of the function f(x)=[x]+[2x]+[3x]++[nx]n(n+1)2x, nN, is ( where [ . ] is the greatest integer function )

A
1.0
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B
1.00
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C
1
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D
01
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Solution

f(x)=[x]+[2x]+[3x]++[nx]n(n+1)2x,
[x]+{x}=x
f(x)=x{x}+2x{2x}+3x{3x}++nx{nx}n(n+1)2x
f(x)=x(1+2+3++n)n(n+1)x2({x}+{2x}+{3x}++{nx})
f(x)=xn(n+1)2n(n+1)2x({x}+{2x}+{3x}++{nx})
f(x)=({x}+{2x}+{3x}++{nx})

We know that period of {x} is 1
Hence, period of f(x) is
L.C.M.(1,12,13,,1n)
=L.C.M.(1,1,,n times)H.C.F.(1,2,3,,n)=1

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