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Question

The general solution of the equation tanx+tan2x+tanxtan2x=1 is

A
x=nπ3+π2
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B
x=nπ3+π12
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C
x=nπ3+π1
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D
x=nπ3+112
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Solution

The correct option is D x=nπ3+π12
tanx+tan2x+tanxtan2x=1tanx+tan2x=1tanxtan2xtanx+tan2x1tanxtan2x=1tan3x=13x=nπ+π4x=nπ3+π12

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