CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The general term in the expansion of (1+3x2x3) is

A
10!r1!r2!r3!(1)r33r22r3xr2+3r3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10!r1!r2!r3!(1)r23r32r3xr2+3r3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
r1+r2+r3=10 10!r1!r2!r3!3r22r3(1)r3xr2+3r3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C r1+r2+r3=10 10!r1!r2!r3!3r22r3(1)r3xr2+3r3
(x1+x2++xk)n=r1+r2+r3++rk=nn!r1!r2!r3!..rk!xr11xr22...xrnn
(1+3x2x3)10=r1+r2+r3=1010!r1!r2!r3!(1)r1(3x)r2(2x3)r3
General term is 10!r1!r2!r3!3r22r3(1)r3xr2+3r3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Coefficients of All Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon