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Question

The geometrical isomerism is shown by


Solution

The correct option is D
Conditions for geometrical isomers:
1) Free rotation must be restricted.
2) Both the terminals must be attached with different groups.
3) Terminals must not be in perpendicular planes.

a has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism

b has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism
c has two same groups attached to the one of the terminal carbon of the double bond so it can't show geometrical isomerism

d has two different groups (H and Cl) attached to the terminal carbon of the both double bond so it can show geometrical isomerism
hence correct option is d.
 

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