Question

The given figure shows the variation of force (Newton) in an elementary system which undergoes a process during which the position of the plunger changes from 0 to 5 $m$ . if the change in internal energy of the system during the process is $2.5J$, the heat absorbed during the process is_____ $KJ$.

• A. 0.03
• B. 0.3
• C. 3.0
• D. 3

Answer 1

The correct option is A 0.03

work done by the system during the process is

$W=\frac{10+5}{2}\times 1+(5-1)\times 5=27.5J$

$Q=\Delta \upsilon +W=2.5+27.5=30J=0.030KJ$

=0.030 KJ