Question

The graph of the linear equation 4x + 3y = 12 cuts the y-axis at the point
(a) (4, 0)
(b) (0, 4)
(c) (0, 3)
(d) (3, 0)

Answer 1

(d) (3, 0)
Given equation: $4x+3y=12$

$\text{Or},x=\frac{12-3y}{4}$

When, y = 0, x = $\frac{12-0}{4}=3$
Thus, the graph cuts the x-axis at (3,0).