CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The green light of wavelengths $$100$$A from a narrow slit is incident on a double slit. If the overall separation of $$10$$ fringes on a screen $$200$$cm away is $$2$$cm, find the slit separation?


A
105 m
loader
B
107 m
loader
C
106 m
loader
D
108 m
loader

Solution

The correct option is C $$10^{-5}$$ m

The wavelength of the green light$$\lambda =100A^{ 0 }$$

 $$=100\times 10^{ - }10m$$

 $$=10^{ - }8m$$

The distance between screen and slit is given as $$D = 200 cm=2m$$.

The separation between 10 fringes is given as $$2$$ cm.

Hence, the fringe width is calculated as$$\beta =\frac { 2 }{ 10 } cm$$

$$=0.2cm$$

$$=0.002m$$

We are asked to calculate the slit width

$$[ d ]$$

The fringe width is calculated as follows $$\beta =\frac { \lambda D }{ d } $$

$$⇒d=\frac { \lambda D }{ \beta } $$

$$=\frac { 10^{ - }8\times 2 }{ 0.002 } m$$

$$=10^{ -5 }m$$


Physics
NCERT
Standard XII

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image