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Question

The ground state energy of hydrogen atom is 13.6 eV. When its electron is in the first excited state, its excitation energy is:

A
10.2 eV
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B
zero
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C
3.4 eV
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D
6.8 eV
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Solution

The correct option is B 10.2 eV
The energy of an electron in Bohr’s orbit of hydrogen atom is given by the expression:

En=13.6Z2n2; [where n = energy state of electron]

For hydrogen Z = 1

E1=13.6eV (given)

For the first excited state, n = 2,

Therefore, E2=13.622eV

E2=3.4 eV

Now, ΔE=E2E1

=3.4(13.6)=10.2eV

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