Question

The H.C.F. $\frac{9}{10}$,$\frac{12}{25}$, $\frac{18}{35}$ and $\frac{21}{40}$:

• A. $\frac{3}{1400}$
• B. $\frac{1}{1200}$
• C. $\frac{1}{2}$
• D. $\frac{3}{2300}$

Answer 1

The correct option is A $\frac{3}{1400}$

H.C.F of $\frac{9}{10}$,$\frac{12}{25}$, $\frac{18}{35}$ and $\frac{21}{40}$

H.C.F of given fractions$=\frac{HCFofnumerators}{LCMofdenominators}$

H.C.F of $9,12,18$ and $21=3$

L.C.M of $10,25,35$ and$40=5\times 2\times 5\times 7\times 4$

$=1400$

Required H.C.F$=\frac{3}{1400}$