The H-C-F- of 9 10- 12 25- 18 35 and 21 40 is-

The correct option is B 3 1400 Required H.C.F. = H.C.F. of 9,12,18,21 L.C.M. of 10,25,35,40 = 3 1400 ...

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Standard X

Chemistry

Volume of Gases and Number of Moles

The H.C.F. of...

Question

The H.C.F. of $\frac{9}{10}$ , $\frac{12}{25}$ , $\frac{18}{35}$ and $\frac{21}{40}$ is:

\frac{3}{5}

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\frac{252}{5}

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\frac{3}{1400}

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\frac{63}{700}

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Solution

The correct option is B $\frac{3}{1400}$
Required H.C.F. $= \frac{H . C . F . o f 9, 12, 18, 21}{L . C . M . o f 10, 25, 35, 40} = \frac{3}{1400}$

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Similar questions

Q. The H.C.F.

\frac{9}{10}

\frac{12}{25}

\frac{18}{35}

and

\frac{21}{40}

Q. The HCF of

\frac{9}{10}, \frac{12}{25}, \frac{18}{35}

and

\frac{21}{40}

Verify each of the following :

(i) $(\frac{5}{7} \times \frac{12}{13}) \times \frac{7}{18} = \frac{5}{7} \times (\frac{12}{13} \times \frac{7}{18})$
(ii) $\frac{- 13}{24} \times (\frac{- 12}{5} \times \frac{35}{36}) = (\frac{- 13}{24} \times \frac{- 12}{5}) \times \frac{35}{36}$
(iii) $(\frac{- 9}{5} \times \frac{- 10}{3}) \times \frac{21}{- 4} = \frac{- 9}{5} \times (\frac{- 10}{3} \times \frac{21}{- 4})$

Q. For the following grouped frequency distribution find the mode:

Class:	$3 - 6$	$6 - 9$	$9 - 12$	$12 - 15$	$15 - 18$	$18 - 21$	$21 - 24$
Frequency:	$2$	$5$	$10$	$23$	$21$	$12$	$3$

Q. Evaluate:

\frac{{(\frac{- 3}{5})}^{3} \times {(\frac{9}{25})}^{2} \times {(\frac{- 18}{125})}^{o}}{(\frac{- 27}{125}) \times (\frac{- 3}{5})}

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The H.C.F. of 910, 1225, 1835 and 2140 is:

The correct option is B 31400Required H.C.F. =H.C.F.of9,12,18,21L.C.M.of10,25,35,40=31400

The H.C.F. of $\frac{9}{10}$ , $\frac{12}{25}$ , $\frac{18}{35}$ and $\frac{21}{40}$ is:

The correct option is B $\frac{3}{1400}$
Required H.C.F. $= \frac{H . C . F . o f 9, 12, 18, 21}{L . C . M . o f 10, 25, 35, 40} = \frac{3}{1400}$