Question

The H - N - H bond angle in $N{H}_3$ is greater than F - N - F bond angle in $N{F}_3$.

• A. False
• B. True

Answer 1

The correct option is B

True

Let take a look at the geometry and & shape of $N{H}_{3}andN{F}_3$

In $N{H}_3$, the bond angle will be around ${107}^o$ instead of ${109.5}^o$ because of one lone pair.

In $N{F}_3$ also, it should be 107° but fluorine is more electronegative than hydrogen and the electron density in the N - F is skewed towards the fluorine.
Therefore, the single bonds are taking less room close to the nitrogen.

So, H - N - H bond angle is greater than F - N - F bond angle in $N{F}_3$.