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Question

The half life period for calalytic decomposition of $$AB_3$$ at 50 mm is found to be 4 hrs and at 100 mm it is 2 hrs. The order of reaction is:


A
3
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B
1
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C
2
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D
0
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Solution

The correct option is C 2
For second order reaction, the expression for the half life period is  $$t_{\frac {1}{2}}= \frac {1} {K}\frac {1}{a)}$$
Thus the half life period is inversely proportional to the concentration for a second order reaction.
 When concentration is doubled from 50 mm to 100 mm, the half life period is reduced to half from 4 hours to 2 hours.

Chemistry
NCERT
Standard XII

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