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Question

The half life period of a first order reaction is $$10$$ minutes. The time required for the concentration of the reactant to change from $$0.08$$ $$M$$ to $$0.02$$ $$M$$ is:


A
10 min
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B
20 min
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C
30 min
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D
40 min
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Solution

The correct option is B $$20\ min$$
$$k=0.693/{ t }_{ 1/2 }\\ =\cfrac { 0.693 }{ 10 } \\ =0.0693{ min }^{ -1 }\\ \therefore \ln { \left( \cfrac { 0.08 }{ 0.02 }  \right) =kt } \\ $$

$$t=\cfrac { \ln { (4) }  }{ k } \\ =\cfrac { \ln { (4) }  }{ 0.0693 } min\\ =20min$$

Chemistry

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