Question

# The half life period of a first order reaction is $$10$$ minutes. The time required for the concentration of the reactant to change from $$0.08$$ $$M$$ to $$0.02$$ $$M$$ is:

A
10 min
B
20 min
C
30 min
D
40 min

Solution

## The correct option is B $$20\ min$$$$k=0.693/{ t }_{ 1/2 }\\ =\cfrac { 0.693 }{ 10 } \\ =0.0693{ min }^{ -1 }\\ \therefore \ln { \left( \cfrac { 0.08 }{ 0.02 } \right) =kt } \\$$$$t=\cfrac { \ln { (4) } }{ k } \\ =\cfrac { \ln { (4) } }{ 0.0693 } min\\ =20min$$Chemistry

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