The half-life period of a first order reaction is $15 m i n u t e .$ How much reaction will be completed in $30 m i n u t e$ ?

75 %

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80 %

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95 %

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100 %

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Solution

The correct option is A $75 %$
$75 %$ completion time
$= T = 2 t_{1 / 2} = 30$ min as $t_{1 / 2} = 15$ min
Reaction will complete $75$ in $30$ min only.

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