The head over a V-notch at the end of a channel is 75 cm. If an error of 0.15 cm is possible In the measurement of the head, then the percentage error in computing the discharge is

0.25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.75

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
0.5

Percentage error in discharge with head, in V-notch is given by

$\frac{d Q}{Q} = \frac{5}{2} \times \frac{d H}{H}$

$= \frac{5}{2} \times \frac{0.15}{75}$

$∴ \frac{d Q}{Q} \times 100 % = 0.5 %$

Suggest Corrections

Similar questions

Q. While conducting the flow measurement using at triangular notch, an error 2% in head over the notch is observed. The percentage error in the computed discharge would be

Q. If the error in the measurement of head in a 'V' notch is 1%, then the error in the measurement of discharge will be

The absolute percentage error in the computed discharge over a rectangular weir corresponding to an absolute error of 1.5% in the measurement of head over the sill of the weir would be

Q. If the length of a cylinder is measured to be

4.28 cm

with an error of

0.01 cm

, then the percentage error in the measurement will be

Q. In measuring the circumference

100

cm of a circle, there is an error of

0.05

cm then percentage error in its area is?

Join BYJU'S Learning Program

The head over a V-notch at the end of a channel is 75 cm. If an error of 0.15 cm is possible In the measurement of the head, then the percentage error in computing the discharge is

The correct option is B 0.5 Percentage error in discharge with head, in V-notch is given by dQQ=52×dHH =52×0.1575 ∴dQQ×100%=0.5%

The correct option is B
0.5

Percentage error in discharge with head, in V-notch is given by

$\frac{d Q}{Q} = \frac{5}{2} \times \frac{d H}{H}$

$= \frac{5}{2} \times \frac{0.15}{75}$

$∴ \frac{d Q}{Q} \times 100 % = 0.5 %$