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Standard XII

Chemistry

Heat of Reaction

The heat comb...

Question

The heat combustion of butane is $2880 k J {m o l}^{- 1}$ . What is the heat liberated by burning $1 k g$ of butane in excess of oxygen supply?

49655 k J

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4965 k J

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4655 k J

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9655 k J

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Solution

The correct option is A $49655 k J$
The heat of combustion of 58 g of butane= $2880 K J m o l^{- 1}$
so, the heat of combustion of 1 Kg of butane = $\frac{2880}{58} * 1000 = 49655 K J$

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The heat combustion of butane is 2880kJmol−1. What is the heat liberated by burning 1kg of butane in excess of oxygen supply?

The correct option is A 49655 kJThe heat of combustion of 58 g of butane= 2880KJmol−1so, the heat of combustion of 1 Kg of butane = 288058∗1000=49655KJ

The heat combustion of butane is $2880 k J {m o l}^{- 1}$ . What is the heat liberated by burning $1 k g$ of butane in excess of oxygen supply?

The correct option is A $49655 k J$
The heat of combustion of 58 g of butane= $2880 K J m o l^{- 1}$
so, the heat of combustion of 1 Kg of butane = $\frac{2880}{58} * 1000 = 49655 K J$