Question

The heat interaction by a system in going through the cyclic process is________J.

• A. $32.416J$
• B. $31.415J$
• C. $27.321J$
• D. $30.50J$

Answer 1

The correct option is B $31.415J$

From first law of thermodynamics,

$\delta Q=dU+\delta W$

Since it is a cyclic process, dU = 0

$\therefore$ $\delta Q=\delta W$

$\Rightarrow$ $\delta Q=Areaofcircle$

$=\frac{\pi \times (200{)}^2}{4}=31415.93kPa-c{m}^3=31.415J$