Question

The height from the center of the earth at which the weight of a body becomes $1/{16}^{\text{th}}$ times its weight on the surface of the earth is -

$R$ is the radius of earth.

• A. $5R$
• B. $2R$
• C. $3R$
• D. $4R$

Answer 1

The correct option is D $4R$

Given,

$W^{\prime }=\frac{1}{16}\times W$

$\Rightarrow \frac{GMm}{R^{\prime 2}}=\frac{1}{16}\times \frac{GMm}{R^2}$

$\Rightarrow R^{\prime }=4R$

Hence, option $\left(D\right)$ is the correct answer.