The height of a conical tent at the center is $5 m$ , the distance of any point on its circular base from the top of the tent is $13 m$ . The area of the slant surface is

144 π s q . m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

130 π s q . m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

156 π s q . m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

169 π s q . m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $156 π s q . m$
Given Height $h = 5$ and Slant height $l = 13$

$\Rightarrow r^{2} = l^{2} - h^{2} = 13^{2} - 5^{2}$

$\Rightarrow r = 12$

Area of slant surface $= π r l$

$= π \times 12 \times 13$

$\Rightarrow$ area of slant surface $= 156 π$ sq.m

Suggest Corrections

Similar questions

There is a tent in conical shape. The slant height of the tent is 14m. If the curved surface area of cone is 308 $m^{2}$ , then base area of tent is

There is a tent in a conical shape. The slant height of the tent is 14 m. If the curved surface area of the tent is 308 m², then what is the base area of the tent? (Take $π = \frac{22}{7}$ )

A circus tent is cylindrical to a height of 8 m surmounted by a conical part. If total height of the tent is 13 m and the diameter of its base is 24 m; calculate: (i) total surface area of the tent, (ii) area of canvas, required to make this tent allowing 10% of the canvas used for folds and stitching.

There is a tent in a conical shape. The slant height of the tent is 14 m. If the curved surface area of the tent is 308 m², then what is the base area of the tent? (Take $π = \frac{22}{7}$ )

There is a conical tent whose slant height is 14 $m$ . If the curved surface area of cone is 308 $m^{2}$ ,then find its base area.

Join BYJU'S Learning Program

The height of a conical tent at the center is 5m, the distance of any point on its circular base from the top of the tent is 13m. The area of the slant surface is

The correct option is C 156πsq.mGiven Height h=5 and Slant height l=13⇒r2=l2−h2=132−52⇒r=12Area of slant surface =πrl =π×12×13⇒area of slant surface =156π sq.m

The height of a conical tent at the center is $5 m$ , the distance of any point on its circular base from the top of the tent is $13 m$ . The area of the slant surface is

The correct option is C $156 π s q . m$
Given Height $h = 5$ and Slant height $l = 13$

$\Rightarrow r^{2} = l^{2} - h^{2} = 13^{2} - 5^{2}$

$\Rightarrow r = 12$

Area of slant surface $= π r l$

$= π \times 12 \times 13$

$\Rightarrow$ area of slant surface $= 156 π$ sq.m