Question

The height of the trapezium having area as 36 cm2 and parallel side as 10 cm and 8 cm is

• A. 2 cm
• B. 4 cm
• C. 6 cm
• D. 8 cm

Answer 1

The correct option is B 4 cm

Let 'a' and 'b' be the parallel sides of the trapezium and 'h' be the height of the trapezium

Then, area of trapezium
$=\frac{1}{2}(\text{sum of parallel sides)}\times \text{height}$
$=\frac{1}{2}\times (a+b)\times h$

$\Rightarrow \text{Area}=\frac{1}{2}\times (10+8)\times h=36$
$\Rightarrow \frac{1}{2}\left(18\right)\times h=36$
$9h=36$
h = 4 cm