Question

The Henry law constant for dissolution of a gas in an aqueous medium is $3\times {10}^2$ atm. At what partial pressure of the gas (in atm), the molality of gas in aqueous solution will be $\frac{5}{9}M$?

• A. $2.2$M
• B. $9$M
• C. $3$M
• D. none

Answer 1

The correct option is C $3$M

We know that, ${\rho }_1=KH\times xx=\frac{n_1}{n_1+n_2}=\frac{\frac{5}{9}}{\frac{5}{9}+\frac{1000}{18}}=9.89\times {10}^{-3}$

Therefore, $\rho =300\times 9.89\times {10}^{-3}=3M$