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Question

The Henry's law constant for the solubility of N2 gas in water at 298K is 1.0 x 105 atm. The mole fraction of N2 is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298K and 5 atm pressure is



A

4 x 10-4

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B

4 x 10-5

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C

5 x 10-4

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D

4 x 10-6

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Solution

The correct option is A

4 x 10-4


PN2=PT×mole fraction=5×0.8=4
From Henry's law
PN2=KH×XN2
XN2=4×105
XN2=nN2nN2+nwater
nN2<<nwater
XN2=nN2nwater
nN2=4×104


Chemistry

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