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Question

The highest boiling point is expected for:

A
Isooctane
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B
n-Octane
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C
2,2,3,3-tetramethylbutane
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D
None of the above
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Solution

The correct option is B n-Octane
Boiling point in alkane depends upon the chains of atoms and the molecular mass of the molecules. Straight-chain molecules have higher boiling point than the branched-chain compounds.
Higher molecular mass molecules have higher boiling point than the lower mass molecules.
All have the same number molecular mass. n-Octane is a straight-chain compound that has a large suface area. So, there are more van der Waals forces of attaraction resulting in a high boiling point.

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